DIVCA (Diseño de Vigas de Concreto Armado) on Windows Pc

Functions:
• Study of different configurations of hyperstatic beams, subjected to stresses (up to 5 supports).
• Calculate and show the reactions of the system.
• Graph the cut and moment diagrams.
• Calculates and displays the maximum values ​​of positive and negative moment.
• Calculates and shows the design condition per section.
• Calculates and shows the required steel area per section according to the requests to which it is submitted.
• Calculate and show the steel distribution according to the selected bar combination.
• Does not need internet.

Limitations:
• Beams with height (h) less than or equal to 100 cm.
• Beams with a height greater than or equal to 25 cm.
• Beams width (b) less than or equal to 100 cm.
• Beams with width greater than or equal to 25cm.
• Beams with height greater than the width (does not admit flat or flat beams).
• Beams with b / h ratio greater than or equal to 0.3.
• Beams with section length (l) less than or equal to 16 times the height (h≥l / 16).
• Beams with section length (l) greater than or equal to 4 times the height (h≤l / 4).
• Beams with flying length less than or equal to 8 times the height (h≥l / 8).
• Beams with a maximum of 4 sections (5 supports).
• At least one load must be applied, if there is no load, a load value equal to zero (0) must be placed.
• The applicable distributable loads will only be linear.
• The loads must be applied per section.
• The initial position (Xi) of the linearly distributed load must not be greater than the final position (Xf).
• The initial position (Xi) of the point load or linearly distributed load must not be greater than the span or flight light.
• The final position (Xf) of the linearly distributed load must not be greater than the span or flight light.
• The average concrete strength at 28 days (f'c) must be greater than or equal to 180 kgf / cm ^ 2 or less or equal 350 kgf / cm ^ 2.
• The yielding tension of the steel must be greater than or equal to 2800 kgf / cm ^ 2 or less than or equal to 5620 kgf / cm ^ 2.
• The steel coating (rc) must be greater than or equal to 4 cm or less or equal to 7.5 cm.
• Is (modulus of elasticity of steel) = 2100000 kgf / cm ^ 2.
• Expose the results to two decimal places.
• The type of problems to solve must not contain loads applied to the element's address.
• They are not considered point loads or linearly distributed upwards, because they require a special design.
• Beams with momentum applied are not considered, because they require a special design.
• Only the following diameters in steel bars are permitted in the detail of the reinforcement steels: Ø 1 ", Ø 7/8", Ø 3/4 ", Ø 5/8", Ø 1/2 ".
• Only a maximum of two diameters can be combined in the detail of the reinforcing steels, this combination is in triads (Ø 1 ", Ø 7/8", Ø 3/4 "or Ø 7/8", Ø 3 / 4 ", Ø 5/8" or Ø 3/4 ", Ø 5/8", Ø 1/2 ").
• A minimum Ø 1/2 "bar is placed in each corner.
• The placement of the steel bars is done in a maximum of two layers.
• The separation of the outermost bar with the face of the beam is 2 cm and the separation between bars of 2.5 cm.
• The maximum steel percentage (ρmax) will be 2.5%.
• If the tensile steel is less than the minimum, the steel to be placed will be the minimum steel area.
• If the compression steel is less than the minimum, the steel to be placed will be the minimum steel area.

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